2.6+day+1

1. A) y= (SqRt x) dy/dt (y)= dx/dt x^ 1/2  dy/dt= 1/2 x^-1/2 dx/dt  dy/dt=(1/2)(4)^-1/2 (3)= 3/4  B)  y= (SqRt x)  dy/dt (y)= dx/dt x^ 1/2 dy/dt= 1/2 x^-1/2 dx/dt 2=(1/2)(25)^(-1/2) dx/dt 2= 1/10 dx/dt

=20 Worked By Hannah Mozafari Checked by Maelle Grenier

7) Y= tanx Dx/dt=2  Dy/dt= sec^2 dx/dt  A) When x=-∏/3 Dy/dt= (2)^2(2) =8 cm/sec B) When x=-∏/4 Dy/dt= (√2)^2(2)  = 4cm/sec  worked by Layne Miller  c) When x=0 dy/dt=(1)^2(2) =2cm/sec 3) xy=4  x(dy/dt)+y(dx/dt)=0  dy/dt=(-y/x)dx/dt  =(-y/8)(10)=-10y/8  dx/dt=(-x/y)dy/dt  =(-1/y)(-6)=6/y  Worked by Nadia Guillen  Checked by Hannah Mozafari! not correct

16. No, because the radius is not constant and could possibly change, which would cause dA/dt to change regardless if dr/dt is constant. worked by Ellen Wagner correct! checked by Sheridan Gabrisch  18. dr/dt= 2in/m r=6” and r=24” V= 4/3πr³ dA/dt= 4πr² dr/dt dA/dt= 4π(6)²(2)= 288π dA/dt= 4π(24)²(2)= 4608π Worked by: Rachel Pearce Checked by Drew Galbraith

19) Worked by Audrey Luecken Correct, Checked by Nadia Guillenv

20.) V=s^3 ds/dt= 3 cm/sec dv/dt=? s=1 cm and s=10cm dv/dt= 3s^2ds/dt dv/dt= 3(1)^2(3)= dv/dt= 9 cm/sec^3 dv/dt= 3(10)^2(3)= dv/dt= 900 cm/sec^3 Worked by morgan cllinkscales correct checked by AAron henderson

21.) Worked by Olga Tobias

Correct! Checked by Brooke Elias 22) worked by Hyun bang correct. checked by Audrey Luecken

23) Worked by Erin Randall V=1/3 ∏r^2h = 1/3∏(9/4h^2)h  = (3∏/4)h^  dv/dt=10  dv/dt=(9/4h^2)h) dh/dt dh/dt=4(dv/dt)/9∏h^2 When h=15 dh/dt=4(10)/9∏(15)^2 dh/dt= 8/405∏ ft/min

Correct-checked by bryan rucker